## Python program to count total repeating digits in a number:

In this post, we will learn how to *count* the *total number of* repeating digits in a given number. For example, for the number *87867*, *7* and *8* are repeating. So, the answer is *2*.

We can solve this problem in different ways. We can either use *two for loops* and find the value by iterating through the *digits* of the number or we can use a *hashmap*.

In this post, I will show you both of these ways.

### Method 1: By using two loops:

In this approach, we will use *two* for loops. Both loops will traverse the *digits* of the numbers from *left* to *right*. Then, for each *digit*, we will compare it with other digits in the number.

If any other digit equal to the current *digit* is found, i.e. the current digit is a *duplicate* digit. We can use the same approach for all other digits to find the total count of *repeating digits* in that number.

### Method 2: By using hashing:

Another, and an *efficient* way is to use a *dictionary*. We can follow the below steps to get the count:

- Initialize one
*empty*dictionary. - Iterate through the digits of the number
*one by one*. -
For each digit, check if any

*key*equal to it exists in the*dictionary*or not. If it doesnâ€™t exists, add it with a value of*1*. If it exists, increment its value by*1*.- The dictionary will hold the
*count*of each digit of the number once each digits are checked.

- The dictionary will hold the
- Once the iteration is completed, check the
*value*of each*key*in the*dictionary*. If any value is more than*1*, that is a repeated value. Calculate the total repeated values and print the result.

Below is the complete program:

```
def find_repeated_count(given_no):
counter_dict = {}
while given_no > 0:
right_digit = given_no % 10
if right_digit in counter_dict:
counter_dict[right_digit] = counter_dict[right_digit] + 1
else:
counter_dict[right_digit] = 1
given_no = int(given_no/10)
total = 0
for key in counter_dict:
if counter_dict[key] > 1:
total += 1
return total
no = int(input('Enter a number :'))
print('Total repeated numbers: {}'.format(find_repeated_count(no)))
```

Here,

*find*repeated*count*method is used to find the*count*of all*repeated digits*in a number.*counter*dict_ is an empty dictionary.- The
*while loop*is used to iterate through the digits of the number one by one. It picks the*rightmost*digit of the number and then*removes*that digit from the number. - The
*if-else*block checks if any*key*equal to the current iterating*digit*is in the*dictionary*or not. If it is not, it adds that*key*with a*value**1*. Else, it increments the current*value*for that*key*by*1*. - The
*for in*loop iterates through the*keys*of the dictionary and finds the total number of*keys*with value more than*1*. - It returns the total count it finds in the
*for-in*loop.

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